## University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson

# Chapter 11 - Section 11.2 - Vectors - Exercises - Page 608: 18

#### Answer

$-4 i-2j +5k$

#### Work Step by Step

Let us consider $P_1$ and $P_2$ as vectors and, a vector $\overrightarrow{P_1P_2}$ can be found as: $\overrightarrow{P_1P_2}=\overrightarrow{P_2}-\overrightarrow{P_1}=\lt 1,2,0 \gt -\lt -3,0,5 \gt =\lt -4,-2,5 \gt$ Hence, our final answers is: $\overrightarrow{P_1P_2}=-4 i-2j +5k$

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