Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.2 - The Mean Value Theorem - Exercises 4.2 - Page 198: 54

Answer

$48$ m/s.

Work Step by Step

Step 1. Given $a=1.6m/s^2$ and $v'=a$, we can write the general equation for the velocity as $v=at+C$ where $C$ is a constant. Step 2. The initial velocity of the rock is zero; we have $v(0)=0$ and $C=0$ Step 3. At $t=30$ sec, we have $v(30)=1.6\times30=48$ m/s.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.