Chapter 4: Applications of Derivatives - Section 4.2 - The Mean Value Theorem - Exercises 4.2 - Page 198: 37

$f(x)=x^2-x$

Since, the derivative is given as: $f'(x)=2x-1$. General form of the function is: $f(x)=x^2-x+C$ Since, the graph of the given function passes through $(0,0)$ . Thus, $f(0)=0 \implies 0^2-0+C \implies C=0$ Hence, $f(x)=x^2-x$