Answer
$s(t)=4.9t^2+5t+10$
Work Step by Step
The derivative of the function Here, $s=\dfrac{ds}{dt}=9.8t+5$ is $s(t)=4.9t^2+5t+C$
Given: $s(0)=10$
This implies that $10=4.9(0)^2+5(0)+C \implies C=10$
Hence, $s(t)=4.9t^2+5t+10$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.2 - The Mean Value Theorem - Exercises 4.2 - Page 198: 41
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