Answer
Absolute maximum at $x=0.$
No absolute minima.
Work Step by Step
The graph of $f$ contains points $(x,f(x)).$
The point ($0,5$) has a higher y-coordinate than any other point on the graph.
$f$ has an absolute maximum at $x=0.$
We can not find a point on the graph such that its y-coordinate is smaller (or equal) than any other y-coordinate (because (2,0) is excluded from the graph).
Whichever $x$ we choose in the (left) vicinity of $x=2$,
we can find $c=2-\displaystyle \frac{2-x}{2}$, which is closer to 2, so the value of $f(c)$ will be smaller than $f(x)$. There are no absolute minima.
