Chapter 4: Applications of Derivatives - Section 4.1 - Extreme Values of Functions - Exercises 4.1 - Page 191: 22

Absolute maximum $f(-4)=0$ and minimum at $f(1)=-5$. See graph.

Step 1. Given the function $f(x)=-x-4, -4\leq x\leq 1$, we have $f(-4)=-(-4)-4=0, f(1)=-1-4=-5$, and we can identify the absolute maximum as $f(-4)=0$ and minimum as $f(1)=-5$ on the given interval. Step 2. See graph.