Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.1 - Extreme Values of Functions - Exercises 4.1 - Page 191: 8

Answer

Absolute maximum at $x=0.$ Absolute minimum at $x=-2$ and $x=2.$

Work Step by Step

The graph of $f$ contains points $(x,f(x)).$ The point (0,2) has a higher y-coordinate than any other point on the graph. $f$ has an absolute maximum at $x=0.$ Points ($-2,0$) and ($2,0$) have a y-coordinate that is less than or equal to any other y-coordinate on the graph. Thus, there is an absolute minimum at $x=-2$ and $x=2.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.