Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 141: 7


The Derivative is: $y'=\sin x\sec^2 x+\sin x$

Work Step by Step

$f(x)=\sin x\tan x$ Using Product Rule to find the Derivative: $y'=h'(x)\cdot g(x)+h(x)\cdot g'(x)$ $y'=(\cos x)(\tan x)+(\sin x)(\sec^2 x)$ $y'=\cos x \frac{\sin x}{\cos x}+\sin x\sec^2 x$ $y'=\sin x\sec^2 x+\sin x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.