Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 141: 40


No, see explanations.

Work Step by Step

Step 1. Given $y=2x+sin(x)$, we have $y'=2+cos(x)$ Step 2. For a horizontal tangent, let $y'=0$, we have $cos(x)=-2$ Step 3. As there is no solution to the above equation, we can not find a horizontal tangent.
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