#### Answer

The Derivative is:
$y'=-10-3\sin x$

#### Work Step by Step

$y=-10x+3\cos x$
Applying Derivative Rules
$y'=(-1)(10)x^{1-1}+(3)(-\sin x)$
$y'=-10-3\sin x$

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Published by
Pearson

ISBN 10:
0-32187-896-5

ISBN 13:
978-0-32187-896-0

The Derivative is:
$y'=-10-3\sin x$

$y=-10x+3\cos x$
Applying Derivative Rules
$y'=(-1)(10)x^{1-1}+(3)(-\sin x)$
$y'=-10-3\sin x$

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