#### Answer

$p^{\prime}=sec^2q$

#### Work Step by Step

As given that
$p=5+\frac{1}{cotq}$
$p=5+tanq$ (because tan $\theta$ and $cot \theta$ are reciprocals)
We differentiate both sides to obtain:
$p^{\prime}=0+sec^2q$
$p^{\prime}=sec^2q$

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Published by
Pearson

ISBN 10:
0-32187-896-5

ISBN 13:
978-0-32187-896-0

$p^{\prime}=sec^2q$

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