Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5: 3

Answer

The Derivative is: $y'=2x\cos x-x^2\sin x$

Work Step by Step

$y=x^2\cos x$ Applying Product Rule $y'=f'(x)\cdot g(x)+f(x)\cdot g'(x)$ $y'=((2)x^{2-1})(\cos x)+(x^2)(-\sin x)$ $y'=2x\cos x-x^2\sin x$
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