Answer
The Derivative is:
$y'=2x\cos x-x^2\sin x$
Work Step by Step
$y=x^2\cos x$
Applying Product Rule
$y'=f'(x)\cdot g(x)+f(x)\cdot g'(x)$
$y'=((2)x^{2-1})(\cos x)+(x^2)(-\sin x)$
$y'=2x\cos x-x^2\sin x$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 141: 3
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