Chapter 3: Derivatives - Section 3.1 - Tangents and the Derivative at a Point - Exercises 3.1 - Page 108: 4

See figure, $3$ and $-3$

At point $P_1$, draw a tangent line to the curve as shown in the figure. We can identify two points on the line $(-2, 0.33)$ and $(-1, 3.33)$; thus the slope of the line can be found as $m_1=\frac{3.33-0.33}{-1+2}=3$. At point $P_2$, draw a tangent line to the curve as shown in the figure. We can identify two points on the line $(2, 0.33)$ and $(1, 3.33)$; thus the slope of the line can be found as $m_2=\frac{3.33-0.33}{1-2}=-3$.