#### Answer

$v(2)=-19.6$

#### Work Step by Step

This is a kinematics question. A function is given to us to represent the height as a function of time.
$h(t)=100-4.9t^2$
Given that the question is asking how fast is the object falling at t=2, it might be advantageous for us to find the instantaneous rate of change of that function at that time, ie. the velocity.
$h'(t)=-(2)(4.9)t=-9.8t$
$h'(2)=-9.8(2)=-19.6$
The object is thus falling down with a velocity of 19.6 meters per second at a time of two seconds.