Answer
The slope of the curve at $ P_1$ is given as $2.75$ and at $ P_2$ is given as $ m_2=-1$.
(Other answers are possible.)
Work Step by Step
1. $ P_1$ appears to be located at (0.2, 1.1). $ P_1$ appears to have the same slope as (0,0). Therefore, $ P_1$ can be given by $\frac{1.1-0}{0.4-0}=2.75$
2. $ P_2$ appears to be located at (1.9, 1.3) and have the same slope as the point (1.8, 1.4). Therefore, $ P_2$ can be given by $\frac{1.3-1.4}{1.9-1.8}=-1$
