Answer
The slope of the curve at $ P_1$ is given as $ m_1=1$ and at $ P_2$ is given as $ m_2=4$.
(Other approximations are possible.)
Work Step by Step
1. From the graph, it can be seen that very near to $ P_1$ is a point $ Q $(0,0).
The slope appears to be linear at point $ Q $ and can be calculated using the near by points (0.2,0.2) and (-0.2,-0.2). Therefore, $ m_1$ is given as $\frac{- 0.2-0.2}{- 0.2-0.2}=1$
2. From the graph, it can be seen that very near to $ P_2$ we can draw a line segment between the points (0.8, 1.6) and (1.2, 2.4). Therefore, $ m_2$ is given as $\frac{2.4-0.8}{1.2-0.8}=4$
