Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 178: 51

Answer

$\frac{dr}{ds}=\frac{2rsin(2s)-sin(2s)}{cos(2s)}$

Work Step by Step

Take the derivative of the equation on each side separately. Apply chain rule when differentiating the "r" variables since we are differentiating with respect to s: $r\times-sin(2s)\times2+\frac{dr}{ds}cos(2s)+2sin(s)\times cos(s)\times1=0$ $-2rsin(2s)+\frac{dr}{ds}cos(2s)+sin(2s)=0$ Move all terms with dr/ds to one side of the equation, and isolate dr/ds: $\frac{dr}{ds}cos(2s)=2rsin(2s)-sin(2s)$ $\frac{dr}{ds}=\frac{2rsin(2s)-sin(2s)}{cos(2s)}$
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