Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 178: 42

Answer

$\frac{dy}{dx}=\frac{5-2x-y}{x+2y}$

Work Step by Step

Take the derivative of the equation on each side separately. Apply chain rule when differentiating the "y" variables since we are differentiating with respect to x: $2x+x\frac{dy}{dx}+y+2y\frac{dy}{dx}-5=0$ Move all terms with dy/dx to one side of the equation, and isolate dy/dx: $x\frac{dy}{dx}+2y\frac{dy}{dx}=5-2x-y$ $\frac{dy}{dx}(x+2y)=5-2x-y$ $\frac{dy}{dx}=\frac{5-2x-y}{x+2y}$
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