## Thomas' Calculus 13th Edition

$y'=3(2x+1)^{1/2}$
Rewrite the equation: $y=(2x+1)(2x+1)^{1/2}=(2x+1)^{3/2}$ Take the derivative of the equation using Power Rule, and Chain Rule: $y'=\frac{3}{2}(2x+1)^{1/2}\times(2+0)=3(2x+1)^{1/2}$