Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 178: 37



Work Step by Step

Rewrite the equation: $y=(2x+1)(2x+1)^{1/2}=(2x+1)^{3/2}$ Take the derivative of the equation using Power Rule, and Chain Rule: $y'=\frac{3}{2}(2x+1)^{1/2}\times(2+0)=3(2x+1)^{1/2}$
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