Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 178: 50



Work Step by Step

Given $q=(5p^2+2p)^{-3/2}$, we have $dq=-\frac{3}{2}(5p^2+2p)^{-5/2}(10pdp+2dp)=-3(5p^2+2p)^{-5/2}(5p+1)dp$ Thus $\frac{dp}{dq}=-\frac{(5p^2+2p)^{5/2}}{15p+3}$
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