Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 84: 24

Answer

$ y $ is continuous on $$(-\infty,\infty)$$

Work Step by Step

Given $$ y=\frac{\sqrt{x^4+1}}{1+\sin^2 x}$$ Since $\sqrt{x^4+1} \neq 0 \ \ \forall x \in R $, and $1+\sin^2 x \neq 0 \ \ \forall x \in R $, So, $ y $ is continuous on $$(-\infty,\infty)$$
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