Answer
$ y $ is continuous on
$$(-\infty,\infty)$$
Work Step by Step
Given $$ y=\sqrt[5]{2-x}$$
Since the fifth root is defined for negative numbers, thus $ y $ is continuous on
$$(-\infty,\infty)$$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 84: 28
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