Answer
$ y $ is continuous in the domain
$$ R-\{-2\}$$
Work Step by Step
Given $$ y=\frac{1}{(x+2)^2}+4$$
Find the zeros of the denominator
$(x+2)^2=0 \Rightarrow x+2=0 \Rightarrow x=-2$
So, $ y $ is continuous in the domain
$ R-\{-2\}$
(All values except -2).
