Thomas' Calculus 13th Edition

$y$ is continuous in the domain $$R-\{2\}$$
Given $$y=\frac{1}{x-2}-3 x$$ Find the zeros of the denominator: $x-2=0 \Rightarrow x=2$ So, $y$ is continuous in the domain $R-\{2\}$ (all values except 2).