Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 84: 11

Answer

Discontinuities are at $ x=0$ (removable) and $ x=1$ (nonremovable).

Work Step by Step

We are given the function $ f(x)$. The function $ f(x)$ has a removable discontinuity at $ x=0$. The discontinuity can be removed by setting $ f(0)=0.$ The discontinuity at $ x=1$ is non-removable -- it is a jump discontinuity.
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