Answer
a. $0$
b. $1$
Work Step by Step
a. As $t\to 4^+$, $\lfloor t\rfloor\to4$, we have $\lim_{t\to4^+}(t-\lfloor t\rfloor)=4-4=0$
b. As $t\to 4^-$, $\lfloor t\rfloor\to3$, we have $\lim_{t\to4^-}(t-\lfloor t\rfloor)=4-3=1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Section 2.4 - One-Sided Limits - Exercises 2.4 - Page 75: 20
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