Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.4 - One-Sided Limits - Exercises 2.4 - Page 75: 51

Answer

(a) $400$ (b) $399$ (c) Does not exist.

Work Step by Step

(a) For the Greatest Integer function, within $400\lt x \lt 400+\delta, 0\lt\delta\lt1$, we have $\lfloor x\rfloor=400$. Thus for any small number $\epsilon\gt0$, we can choose $\delta=0.5$ so that for all $x$ in the interval of $400\lt x \lt 400+0.5$, we have $|\lfloor x\rfloor-400|=0\lt\epsilon$, which proves that $\lim_{x\to400^+}\lfloor x\rfloor=400$ (b) Similarly, within $400-\delta\lt x\lt 400, 0\lt\delta\lt1$, we have $\lfloor x\rfloor=399$. Thus for any small number $\epsilon\gt0$, we can choose $\delta=0.5$ so that for all $x$ in the interval of $400-0.5\lt x\lt 400$, we have $|\lfloor x\rfloor-399|=0\lt\epsilon$, which proves that $\lim_{x\to400^-}\lfloor x\rfloor=399$ (c) Because $\lim_{x\to400^-}\lfloor x\rfloor\ne\lim_{x\to400^+}\lfloor x\rfloor$, $\lim_{x\to400}\lfloor x\rfloor$ does not exist.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.