Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 58: 79


a. $5$ b. $5$

Work Step by Step

a. Given $\lim\limits_{x \to 2}\frac{f(x)-5}{x-2}=3$, we have $\lim\limits_{x \to 2}f(x)=\lim\limits_{x \to 2}3(x-2)+5=5$ b. Given $\lim\limits_{x \to 2}\frac{f(x)-5}{x-2}=4$, we have $\lim\limits_{x \to 2}f(x)=\lim\limits_{x \to 2}4(x-2)+5=5$
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