## Thomas' Calculus 13th Edition

a. see the table. b. see the graph. c. $-6$
a. See the table above. b. See the graph above. As x gets closer to -3, $f(x)$ approaches -6. c. $\lim\limits_{x \to -3}\frac{x^2-9}{x+3}=\lim\limits_{x \to -3}\frac{(x-3)(x+3)}{x+3}=\lim\limits_{x \to -3}(x-3)=-6$