Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 58: 67

Answer

a. see the table. b. see the graph. c. $-6$
1567331554

Work Step by Step

a. See the table above. b. See the graph above. As x gets closer to -3, $ f(x)$ approaches -6. c. $\lim\limits_{x \to -3}\frac{x^2-9}{x+3}=\lim\limits_{x \to -3}\frac{(x-3)(x+3)}{x+3}=\lim\limits_{x \to -3}(x-3)=-6$
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