Answer
a. see the table.
b. see the graph.
c. $-6$
Work Step by Step
a. See the table above.
b. See the graph above. As x gets closer to -3, $ f(x)$ approaches -6.
c. $\lim\limits_{x \to -3}\frac{x^2-9}{x+3}=\lim\limits_{x \to -3}\frac{(x-3)(x+3)}{x+3}=\lim\limits_{x \to -3}(x-3)=-6$
