Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 58: 71

Answer

a. See the table, $2.000$ b. See the graph, $2.0$ c. $2$

Work Step by Step

a. From the table, $\lim\limits_{x \to -1}\frac{x^2-1}{|x|-1}\approx 2.000$ b. From the graph, $\lim\limits_{x \to -1}\frac{x^2-1}{|x|-1}\approx 2.0$ c. $\lim\limits_{x \to -1}\frac{x^2-1}{|x|-1}=\lim\limits_{x \to -1}\frac{(x+1)(x-1)}{-x-1}=\lim\limits_{x \to -1}(-x+1)=2$
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