Answer
a. see the table, $ -0.125$
b. see the graph, $ -0.13$
c. $-\frac{1}{8}$
Work Step by Step
a. From the table, $\lim\limits_{x \to -6}\frac{x+6}{x^2+4x-12}\approx -0.125$
b. From the graph, $\lim\limits_{x \to -6}\frac{x+6}{x^2+4x-12}\approx -0.13$
c. $\lim\limits_{x \to -6}\frac{x+6}{x^2+4x-12}=\lim\limits_{x \to -6}\frac{1}{x-2}=-\frac{1}{8}$
