Answer
(a) $4$ (b) $-2$
Work Step by Step
Given $lim_{x\to-2}\frac{f(x)}{x^2}=1$, we have (a) $\frac{lim_{x\to-2}f(x)}{lim_{x\to-2}x^2}=1$ or $lim_{x\to-2}f(x)=lim_{x\to-2}x^2=(-2)^2=4$; (b) $lim_{x\to-2}\frac{f(x)}{x}=\frac{lim_{x\to-2}f(x)}{lim_{x\to-2}x}=\frac{4}{-2}=-2$
