Answer
1
Work Step by Step
$\int^{ln2}_{0} \int^{e^x}_{0} dydx$
=$\int^{ln2}_{0}e^xdx$
=[e^x]^{ln2}_0
=2-1
=1
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 15: Multiple Integrals - Section 15.3 - Area by Double Integration - Exercises 15.3 - Page 887: 5
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