#### Answer

$\frac{32}{3}$

#### Work Step by Step

$\int_{0}^{2} \int^{0}_{x^2-4}dydx+\int_{0}^{{\sqrt{x}}}dydx$
=$\int_{0}^{2}(4-x^2)dx+\int_{0}^{4}x^{1/2}dx$
=$[4x-\frac{x^3}{3}]^2_0+[\frac{2}{3}x^{3/2}]^4_0=(8-\frac{8}{3})+\frac{16}{3}=\frac{32}{3}$

Chegg costs money, GradeSaver solutions are free!

Published by
Pearson

ISBN 10:
0-32187-896-5

ISBN 13:
978-0-32187-896-0

$\frac{32}{3}$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.