#### Answer

2

#### Work Step by Step

$\int^{2}_{0} \int^{2-x}_{0} dy dx$
=$\int^{2}_{0}(2-x)dx$
=$[2x-\frac{x^2}{2}]^2_0$
=2

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Published by
Pearson

ISBN 10:
0-32187-896-5

ISBN 13:
978-0-32187-896-0

2

$\int^{2}_{0} \int^{2-x}_{0} dy dx$
=$\int^{2}_{0}(2-x)dx$
=$[2x-\frac{x^2}{2}]^2_0$
=2

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