Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.3 - Area by Double Integration - Exercises 15.3 - Page 887: 16



Work Step by Step

$\int^{2}_{-1} \int^{y+2}_{y^2}dxdy$ =$[\frac{}{}+2y-\frac{y^3}{3}]_{-1}^2$ =(2+4-8/3)-(1/2-2+1/3) =5-1/2=9/2
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