Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Section 11.1 - Parametrizations of Plane Curves - Exercises 11.1 - Page 647: 4

Answer

$y=2-\displaystyle \frac{2}{3}x,\qquad 0 \leq x \leq 3$

Work Step by Step

Express $t$ in terms of one variable and substitute it into the other equation. $x=3-3t\Rightarrow\quad \left[\begin{array}{ll} t & x\\ 0 & 3\\ 1/3 & 2\\ 1 & 0 \end{array}\right]\Rightarrow\quad 0 \leq x \leq 3$ $3t=3-x$ $t=\displaystyle \frac{3-x}{3}$ $y=2(\displaystyle \frac{3-x}{3})\Rightarrow\quad $ $ \fbox{$ y=2-\displaystyle \frac{2}{3}x, 0 \leq x \leq 3 $}$ To graph, create a table using several values for $t$, and then calculate $(x(t), y(t)),$ plotting the points as you go. Join with a smooth curve, noting the direction in which $t$ increases.
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