Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Section 11.1 - Parametrizations of Plane Curves - Exercises 11.1 - Page 647: 22

Answer

$x=t$ $y=-\dfrac{5}{4}t+\dfrac{7}{4};(-1\leq t \leq 3)$ (other answers are also possible)

Work Step by Step

The slope of a line between two points is defined as follows: $m=\dfrac{-2-3}{3-(-1)}=-\dfrac{5}{4}$ The point-slope equation is: $y-y_0=m(x-x_0)$ This implies that $s y-(-2)=-\dfrac{5}{4}(x-3)=-\dfrac{5}{4}x+\dfrac{7}{4}$ Let us consider $x=t$ Then, we get $y=-\dfrac{5}{4}t+\dfrac{7}{4}$ Hence, $x=t$ $y=-\dfrac{5}{4}t+\dfrac{7}{4};(-1\leq t \leq 3)$ (other answers are also possible)
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