Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 11: Parametric Equations and Polar Coordinates - Section 11.1 - Parametrizations of Plane Curves - Exercises 11.1 - Page 647: 33

Answer

$x=2+ \cos \theta$;$y=\sin \theta$; $0\leq \theta \leq 2 \pi$

Work Step by Step

The parametric equations are: $x=a \cos \theta; y= a\sin \theta$; $(0\leq \theta \leq 2 \pi)$ Since, $y=\sin \theta$ and $ x -2 = \cos \theta$ This can be re-written as: $x=2+ \cos \theta$ Thus, we have $x=2+ \cos \theta$;$y=\sin \theta$; $(0\leq \theta \leq 2 \pi)$
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