Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.6 - Alternating Series and Conditional Convergence - Exercises 10.6 - Page 603: 51

Answer

$$2 \times 10^{-11}$$

Work Step by Step

Consider: $S_n=a_1-a_2+......+(-1)^{n+1}a_n$ and $$|S-S_n|=\leq |a_{n+1}| \\ \implies |\space Error |=|S-S_4| \leq |a_{4+1}|=|a_5| \\ \implies |(-1)^6 \times (\dfrac{0.01}{5})^5| \\=2 \times 10^{-11}$$
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