Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.6 - Alternating Series and Conditional Convergence - Exercises 10.6 - Page 603: 45

Answer

Absolutely Convergent

Work Step by Step

Let us apply the Ratio Test to the given series. $\lim\limits_{n \to \infty} |\dfrac{u_{n+1}}{u_n}|=\lim\limits_{n \to \infty} \dfrac{1+e^{-2n}}{e+e^{-(2n-1)}} \\=\lim\limits_{n \to \infty} \dfrac{1+0}{e+0} \\=\dfrac{1}{e} \lt 1$ This implies that the series is Absolutely Convergent by the ratio test.
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