Answer
Solution set = $\displaystyle \{\frac{7}{6},\frac{25}{6}\}$
Work Step by Step
Use properties from the table 'Absolute Values and Intervals"
Here: property 5: $|x|=a \Leftrightarrow x=\pm a,\ \quad $(for any positive number a)
Thus:
$8-3s=\displaystyle \pm\frac{9}{2}\qquad $... multiply with 2
$ 16-6s=\pm 9\qquad$ ... add $-16$
$-6s=-16\pm 9\qquad $divide with $(-6)$
$s=\displaystyle \frac{-16\pm 9}{-6}$
$\displaystyle \frac{-16+9}{-6}=\frac{-7}{-6}=\frac{7}{6}$
$\displaystyle \frac{-16-9}{-6}=\frac{-25}{-6}=\frac{25}{6}$
Solution set = $\displaystyle \{\frac{7}{6},\frac{25}{6}\}$
