#### Answer

$x\in(-1,3)$

#### Work Step by Step

The square root function is defined for nonnegative real numbers, and is an increasing function.
This means that if a and b are nonnegative,
$a \lt b\Rightarrow\sqrt{a} \lt \sqrt{b}$
An alternate definition of the absolute value is $|x|=\sqrt{x^{2}}$.
Both sides of the inequality sign are nonnegative, so we may take the square root of both sides, with the direction of inequality being unchanged:
$\sqrt{(x-1)^{2}} \lt \sqrt{4}$
$|x-1| \lt 2$
$-2 \lt |x-1| \lt 2$
add 1 to each side:
$-1 \lt |x| \lt 3$
This solution set in interval form is
$x\in(-1,3)$