## Thomas' Calculus 13th Edition

$-2\lt x\lt 2,\qquad$ or, $x\in(-2,2)$
Use properties from the table, 'Absolute Values and Intervals" Applying Property 6: $|x|\lt a\quad\Leftrightarrow\quad -a\lt x\lt a, \quad$ for a = positive number $|x|\lt 2\quad\Leftrightarrow\quad -2\lt x\lt 2$ This is an open interval, $(-2,2)$ (see table: "Types of intervals".)