## Thomas' Calculus 13th Edition

$x\displaystyle \in(-\frac{1}{2},3]$
$\left|x\right|\leq 3\quad \Leftrightarrow\quad x\in[-3,3]$ (property 8 from the table 'Absolute Values and Intervals") At the same time, $x\displaystyle \gt -1/2 \quad \Leftrightarrow\quad x\in(-\frac{1}{2},\infty]$ So, x is in the intersection of these intervals (see image) $x\displaystyle \in(-\frac{1}{2},3]$