Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 11 - Section 11.4 - The Chain Rule - Exercises - Page 831: 63

Answer

$\displaystyle \left.\frac{dx}{dy}\right|_{x=1}=\frac{1}{4}$

Work Step by Step

$\displaystyle \frac{dx}{dy}=\frac{1}{(\frac{dy}{dx})},\qquad \frac{dy}{dx}\neq 0$ $\displaystyle \frac{dy}{dx}=\frac{d}{dx}[3(2x)-2]=6x-2$ $\left.\frac{dy}{dx}\right|_{x=1}=6-2=4$ $\displaystyle \left.\frac{dx}{dy}\right|_{x=1}=\frac{1}{4}$
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