Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 11 - Section 11.4 - The Chain Rule - Exercises - Page 831: 55

Answer

$\displaystyle \frac{dV}{dt}=4\pi r^{2}\cdot\frac{dr}{dt}$

Work Step by Step

$r=r(t)$ so, by the chain rule, $\displaystyle \frac{dV}{dt}=\frac{dV}{dr}\frac{dr}{dt}$ $\displaystyle \frac{ds}{dr}=\frac{d}{dr}[\frac{4\pi}{3}\cdot r^{3}]=\frac{4\pi}{3}\cdot 3r^{2}=4\pi r^{2}$ $\displaystyle \frac{dV}{dt}=4\pi r^{2}\cdot\frac{dr}{dt}$
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