Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 11 - Section 11.4 - The Chain Rule - Exercises - Page 831: 56

Answer

$\displaystyle \frac{dA}{dt}=8\pi r\cdot\frac{dr}{dt}$

Work Step by Step

$r=r(t)$ so, by the chain rule, $\displaystyle \frac{dA}{dt}=\frac{dA}{dr}\frac{dr}{dt}$ $\displaystyle \frac{ds}{dr}=\frac{d}{dr}[4\pi\cdot r^{2}]=4\pi\cdot 2r=8\pi r$ $\displaystyle \frac{dA}{dt}=8\pi r\cdot\frac{dr}{dt}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.