Answer
$\dfrac{y}{x(y-1)}$
Work Step by Step
We have: $\ln (\dfrac{y}{x})=y$
or, $\ln y-\ln x=y$
We differentiate both sides with respect to $x$.
$\dfrac{1}{y}\dfrac{dy}{dx}-\dfrac{1}{x}=\dfrac{dy}{dx}+y$
This implies that $(\dfrac{1}{y}-1)\dfrac{dy}{dx}=\dfrac{1}{x}$
Therefore, $\dfrac{dy}{dx}=\dfrac{y}{x(y-1)}$
