## Calculus with Applications (10th Edition)

$\dfrac{2}{p+\sqrt{p(p-2)}}$
Rationalize the numerator by multiplying $\sqrt{p}+\sqrt{p-2}$ to both the numerator and the denominator to have: $=\dfrac{\sqrt{p}-\sqrt{p-2}}{\sqrt{p}} \cdot \dfrac{\sqrt{p}+\sqrt{p-2}}{\sqrt{p}+\sqrt{p-2}} \\=\dfrac{p-(p-2)}{p+\sqrt{p(p-2)}} \\=\dfrac{p-p-(-2)}{p+\sqrt{p(p-2)}} \\=\dfrac{0+2}{p+\sqrt{p(p-2)}} \\=\dfrac{2}{p+\sqrt{p(p-2)}}$